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lol... try ah...
Input Voltage
= 240( sin 2*pi*50 + jcos 2*pi*50)
= 240( -0.26 +j0.96)
= -62.4 +j230.4
Total input impedence
= 1/(1/z1 + 1/z2 + 1/z3)
=2.33+j1.1
Total current
= Total voltage/Total impedence
= 16.27+j91.2
Total input power
=| Re {VI} |= 22028
Total reactant power
= | Img {VI} | = 1941
jwC + 1/Zin = Re number
Hence,
if 1/Zin = 0.35-j0.17,
jwC = j0.17
C = 5.4x 10E-4 F
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