binomial

• ItchyArmpit

  26 Apr 09, 12:28

  hey guys.. i keep getting confused over this simple thing... altho simple but gave me lotta problems..

  whenever i do binomial, there is this (1/2x)^n-1   

  how do i expand this?

  i always dun know issit [1/(2^n-1.x^n-1)] or [1/(2.x^n-1)]

  or issit other answers? teach me please thanks.. i know this looks simple but i really need help on this.. thanks

   

  IA

• ItchyArmpit

  26 Apr 09, 12:49

  o i know how to do le... but another question here...

  2^n-1 = 5n^-1        solve this.

  please help... thanks!

• wee_ws

  26 Apr 09, 13:15

  Originally posted by ItchyArmpit:

  o i know how to do le... but another question here...

  2^n-1 = 5n^-1        solve this.

  please help... thanks!

  Hi,

    It's not possible to solve algebraically. Try graphing them. Thanks!

  Cheers,
  Wen Shih

• wee_ws

  26 Apr 09, 13:18

  Originally posted by ItchyArmpit:

  hey guys.. i keep getting confused over this simple thing... altho simple but gave me lotta problems..

  whenever i do binomial, there is this (1/2x)^n-1   

  how do i expand this?

  i always dun know issit [1/(2^n-1.x^n-1)] or [1/(2.x^n-1)]

  or issit other answers? teach me please thanks.. i know this looks simple but i really need help on this.. thanks

   

  IA

  Hi,

    Do you mean (1/2 x)^(n - 1)?

    Assuming it is (1/2 x)^(n - 1), it will be simplified to (1/2 x)^ n . (1/2 x)^(-1) by the rule of indices.

    Thanks!

  Cheers,
  Wen Shih

• ItchyArmpit

  26 Apr 09, 13:23

  omg thanks so much.. u helped a lot.. thanks