The equation of the line p is 3y - x = 10. Find
i) the gradient of the line p
ii) The equation of the line parallel to p and which passes through the point (6, 10)
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The graph, y = (x+4)(x+1) cuts the x axis at A and the y-axis at B
Find the coordinates of A and B
I am very bad at Graphs. Could anyone teach me??
Originally posted by Pfft:The equation of the line p is 3y - x = 10. Find
i) the gradient of the line p
ii) The equation of the line parallel to p and which passes through the point (6, 10)
_____________________________________________________________________
The graph, y = (x+4)(x+1) cuts the x axis at A and the y-axis at B
Find the coordinates of A and B
I am very bad at Graphs. Could anyone teach me??
i) Rearrange the equation having y as the subject and the coefficient of x will be your gradient
ii) Using the gradient obtained, sub it into the equation y=mx+c to find c and you have the equation.
iii) When a curve cuts the x-axis, all the y values are 0 and when it cuts the y-axis, x is 0. To solve for A and B, its simple (x+4)=0 and (x+1)=0 since you know that at point A and B the y value is 0 so solving you can get the x values from there.
Originally posted by dkcx:i) Rearrange the equation having y as the subject and the coefficient of x will be your gradient
ii) Using the gradient obtained, sub it into the equation y=mx+c to find c and you have the equation.
iii) When a curve cuts the x-axis, all the y values are 0 and when it cuts the y-axis, x is 0. To solve for A and B, its simple (x+4)=0 and (x+1)=0 since you know that at point A and B the y value is 0 so solving you can get the x values from there.
Which question are you talking about? the top one or the bottom one?
and could u gimme a sample answer?
hes answering all the questions that you have.
i) equations of a line are usually y = mx + c where m is gradient and c is y-intercept. When you rearrange the equation to make it as the one stated above, to find gradient, you find the coefficient of x, which is m.
ii) now you have the gradient, since both lines are parallel, both lines should share the same gradient. using y = mx + c again, substitute the values in and you can find your answer.
Originally posted by Music-Life:hes answering all the questions that you have.
i) equations of a line are usually y = mx + c where m is gradient and c is y-intercept. When you rearrange the equation to make it as the one stated above, to find gradient, you find the coefficient of x, which is m.
ii) now you have the gradient, since both lines are parallel, both lines should share the same gradient. using y = mx + c again, substitute the values in and you can find your answer.
I don't understand but is the answer
3y = x + 10
y = 1/3x + 10/3 ?
gradient = 1/3 ?
Yeah.
Originally posted by Pfft:Which question are you talking about? the top one or the bottom one?
and could u gimme a sample answer?
part i) and ii) are as your question and iii) is the bottom question