Solving this equation

• fireice rox

  21 May 09, 19:24

  I have a problem solving this equation:

  (5/a2 -1) - (7/2a+2) = 3/1-a

  How to get the rid of the denominator?

   

• yiha093

  21 May 09, 19:33

  times whole eqn by the denominator

• dadeadman1337

  21 May 09, 19:33

  (a^2 -1) is the same as (a+1)(a-1)

  (2a+2) is 2(a+1)

  I supp you know how to frm here

• fireice rox

  21 May 09, 20:09

  thanks for the fast response. the answer is 23 but i get -3/2 leh

• Forbiddensinner

  21 May 09, 21:51

  Originally posted by fireice rox:

  I have a problem solving this equation:

  (5/a2 -1) - (7/2a+2) = 3/1-a

  How to get the rid of the denominator?

   

  Okay, figured out myself what you are typing.

  5/(a^2-1) - 7/(2a+2) = 3/(1-a)

  5/((a+1)(a-1)) - 7/(2(a+1)) = -3/(a-1)

  10/(2(a+1)(a-1)) - 7(a-1)/(2(a+1)(a-1)) = -6(a+1)/(2(a+1)(a-1))

  .= > 10 - 7(a-1) + 6(a+1) = 0

  10 - 7a + 7 + 6a + 6 = 0

  23 - a = 0

  a = 23