http://img44.imageshack.us/i/6circles.jpg/
http://img198.imageshack.us/i/6circles2b.jpg/
hi i an do (a) and (b), am stuck at (c), finding the length OB
AB=2r (r is radius of small cylinder)
AB=OA=OB (since triangle is equilateral)
therefore, OB=2r
B is center of cylinder, therefore, B to closest side of barrel (lets call it point X)=r
Since OB=AB, OX=radius of barrel=3r (OB+BX)=(given in qn but cant see clearly, call it R)
So, OB=2r=R/3 *2
Originally posted by Divanhot:http://img44.imageshack.us/i/6circles.jpg/
http://img198.imageshack.us/i/6circles2b.jpg/
hi i an do (a) and (b), am stuck at (c), finding the length OB
Since its equilateral triangle, OB = BC which means OB = 2 X radius of the circle. Therefore, 84 = 3 X radius of circle so OB = 84 / 3 X 2 = 56cm
