Qn: 93 metal bars are manufactured by one machine. The length, x in metres, of each of the bars, is recorded.
The results are as follows: ∑x=102.4 and ∑x^2=   329.11
Based on the given question, how do I calculate the Variance and what does it mean?
The formula I have is
[ ∑ ( x_i - x*)^2] / n
x* = Mean of x. Dunno how to type it.
I think u need to expand the formula above and then sub in the values.
You can start by calculating the mean which is 102.4 / 93
But how do I get the values from ∑x=102.4 and ∑x^2=   329.11 only? The mean I calculated as 1.10m, then how do I proceed?
You know how to expand the formula?
You will get [(x_i)^2 - 2(x_i)(x*) + (x*)^2] / n
Use ∑x=102.4 and ∑x^2=   329.11 and somehow try to sub it into the equation together with the mean u found.
My mind is a bit groggy.
But I think it should be something like this.
Maybe can get the experts to explain clearer to u.
Originally posted by charlize:My mind is a bit groggy.
But I think it should be something like this.
Maybe can get the experts to explain clearer to u.
Originally posted by marcteng:
are you maths expert lol
Do I sound like a math expert?
Like the rest of you, I have problems finishing my homework too.
Hi SBS1984E,
Variance refers to the average of the squares of the differences between x and x-bar, as you may observe from the formula. It looks at the spread of observations of x from the mean x-bar.
What measure are you calculating, is it sample variance or the unbiased estimate of the population variance?
Given the sum of x and x^2 in the problem, the formula you have is certainly not appropriate. Do look up your notes on another equivalent formula that involves the sum of x and x^2.
Thanks!
Cheers,
Wen Shih
Originally posted by SBS1984E:Qn: 93 metal bars are manufactured by one machine. The length, x in metres, of each of the bars, is recorded.
The results are as follows: ∑x=102.4 and ∑x^2=   329.11
Based on the given question, how do I calculate the Variance and what does it mean?
The formula I have is
[ ∑ ( x_i - x*)^2] / n
x* = Mean of x. Dunno how to type it.
Variance is the square of standard deviation.
I believe the qn is on sample variance.
Since ∑x=102.4, the mean, x* = 102.4 / 93 = 1.10
Since [ ∑( x_i - x*)^2] / n = [∑( x_i)^2] / n - (x*) ^2
Variance = 329.11/93 - (1.10)(1.10) = 2.33
That's what I think...
Also standard deviation formula from wiki is
So answer should be
329.11/93 - (102.4/93)^2, same as lianmaster
Die.
I am going to fail my maths soon.
Thanks! All. Erm Eagle, the "E" is representing what? The Sigma Sign?
This one not related to your question... I just itchy hand post only
It means Expectation of X
Originally posted by SBS1984E:
Thanks! All. Erm Eagle, the "E" is representing what? The Sigma Sign?
E is the expected value. E(X) is the expected value of X.
The sigma sign means summation, which is the sum of all the values.
Originally posted by charlize:Die.
I am going to fail my maths soon.
There is still hope, get eagle to give you maths tuition.
Originally posted by SBS1984E:Qn: 93 metal bars are manufactured by one machine. The length, x in metres, of each of the bars, is recorded.
The results are as follows: ∑x=102.4 and ∑x^2=   329.11
Based on the given question, how do I calculate the Variance and what does it mean?
The formula I have is
[ ∑ ( x_i - x*)^2] / n
x* = Mean of x. Dunno how to type it.
To simplify the variance formula first
∑ ( x - x*)^2
Variance = ------------------- where x* is the mean of x
n
∑ ( x^2 - 2xx* + x*^2)
Variance = ----------------------------
n
∑ x^2 - 2x*∑ x + ∑ x*^2
Variance = -------------------------------
n
∑ x^2 ∑ x nx*^2
Variance = ------- - 2x*--------- + ---------
n n n
∑ x^2
Variance = ------- - x*^2
n
Varaince = [ ∑ x^2 ] /n - [ ∑ x /n ] ^ 2
Since ∑x=102.4 , ∑x^2=   329.11, n = 93
Variance = 329.11/93 - [102.4/93]^2 = 2.33
Originally posted by deepak.c:
There is still hope, get eagle to give you maths tuition.
No money.
Poor students really are disadvantaged.
Haiz.
Originally posted by charlize:No money.
Poor students really are disadvantaged.
Haiz.
Not necessary.
Just need to work harder with the right mentality and the right methods.
I only found out many of my peers had tuition in JC recently... and I didn't have it
In a way, I was free to explore and "invent" many of my shortcut tips and tricks which I gladly teach to many people now, both on sgforums, sgclub and in tuition