*Okay so the original topic may have the wrong title so heres a remake
Firstly, hi everyone this would be my first post here. Secondly I got some considerably simple yet I-cant-seem-to-get-it mahematics questions that Ihave been pondering for a while now. They would be ..
m/n = 2/p(a+3b/2a+7b^1/3)
Where I will have to make a the subject of the formula
(m+n/m-n)^1/2 = p+q/p-q
Where I will have to make n the subject of the formula
It would be better to write down the equations on a piece of paper and I apologize for the lack of proper symbols as the mathematical symbols on my computer are limited. Thank you for your help.
Originally posted by Anthiadon:*Okay so the original topic may have the wrong title so heres a remake
Firstly, hi everyone this would be my first post here. Secondly I got some considerably simple yet I-cant-seem-to-get-it mahematics questions that Ihave been pondering for a while now. They would be ..
m/n = 2/p(a+3b/2a+7b^1/3)
Where I will have to make a the subject of the formula
(m+n/m-n)^1/2 = p+q/p-q
Where I will have to make n the subject of the formula
It would be better to write down the equations on a piece of paper and I apologize for the lack of proper symbols as the mathematical symbols on my computer are limited. Thank you for your help.
Need to clarify, for Q1, is it (2a+7b)^(1/3) or is it 7b^(1/3) or is it (a+3b/2a+7b)^(1/3)?
For Q2,
(m+n/m-n)^1/2 = p+q/p-q
(m+n/m-n) = (p+q/p-q)^2
(m-n)(p+q)^2 = (m+n)(p-q)^2
m(p+q)^2 - n(p+q)^2 = m(p-q)^2 + n(p-q)^2
n(p+q)^2 + n(p-q)^2 = m(p+q)^2 - m(p-q)^2
n = [m [(p+q)^2 - (p-q)^2]] / [(p+q)^2 + (p-q)^2]
Originally posted by marcteng:why dun you ask your teacher, tutor or lecturers lol
Let me give you some hints.
School re-opens on next Monday.
Today is the 2nd last day of holiday.
Many students have the bad habit of waiting till a certain period of time before doing their holiday assignments.
Okay, with that the answer is pretty obvious.
Firstly I finished most of my assignments before this and am skipped this particular question. Secondly my teachers, be it tuition or school, are out for the moment, and not in that way. Thirdly thank you for the answer. Good night.
its (a+3b/2a+7b)^(1/3)
Originally posted by Anthiadon:its (a+3b/2a+7b)^(1/3)
Welcome back, good night.
m/n = 2/ p (a+3b/2a+7b)^(1/3)
2n = pm(a+3b/2a+7b)^(1/3)
8n^3 = (pm)^3(a+3b/2a+7b)
16an^3 + 56bn^3 = a(pm)^3 + 3b(pm)^3
16an^3 - a(pm)^3 = 3b(pm)^3 - 56bn^3
a [ 16n^3 - (pm)^3 ] = b [ 3(pm)^3 - 56n^3 ]
a = b [ 3(pm)^3 - 56n^3 ] / [ 16n^3 - (pm)^3 ]
Thank you, I appreciate it.