Hello,
1) i dont know how to find the horizontal asymptote for qn 3ii(qn is in the middle of the picture).
The qn is below. Resolution shld be pretty clear i hope
http://img142.imageshack.us/i/lgim0031.jpg/
2)Anotehr thing is for a disjointed graph, how do you determine which is the maximum and minimum pt. I find this problem when i am doing transformation to a reciprocal graph.
Thanks alot as usual!! :):)
me going to sleep liao, tmr still got work
1) Basically just do a normal long division. From the normal long division, you can find the horizontal asymptote as I have taught.
Y = f(x) + g(x) / (/\x+1)(x+4)
so y = f(x) is the asymptote. Since in this case, this f(x) is a constant, it will give us a horizontal asymptote.
Understand that the question is put that way because
-1 and 1/3 will make it a factor of the numerator,
0 is already done
1/4 will make the denominator a (x+4)^2
2) as long as you see a U-shape, it will give a minimum point
a n-shape will give u a maximum point. The main thing is about stationary points.
remember fro reciprocal graphs, whatever is above the x-axis remains above. Whatever below remains below.
