Quadratic Formula Help

• kittyslut

  7 Jul 09, 21:14

  2x^2 - kx  = 2 - k, where k is a positive constant

  need help in solving this using quadratic formula. thanks.

• ThunderFbolt

  7 Jul 09, 23:59

  Just do as per normal? 

   

  2x^2 - kx  = 2 - k

  2x^2 - kx  + (k - 2) = 0

  x = ( k +/- sqrt(k^2 - 8(k-2))/4

     = (k-2)/2 or 1

• Forbiddensinner

  8 Jul 09, 12:05

  Originally posted by ThunderFbolt:

  Just do as per normal? 

   

  2x^2 - kx  = 2 - k

  2x^2 - kx  + (k - 2) = 0

  x = ( k +/- sqrt(k^2 - 8(k-2))/4

     = (k-2)/2 or 1

  I think she either forgotten or haven't learn about

  x = [ -b +/- Sq rt (b^2 -4ac) ] / 2a , where a = 2, b = -k, c = k - 2