P6 Maths - Volume
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cannot see your first post... but for the second one is like damn easy lor... still need help meh?
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Originally posted by caleb_chiang:cannot see your first post... but for the second one is like damn easy lor... still need help meh?
Please do not post something like this the next time here.
This is a P6 question, not a sec 2/3 question, and it does pose quite some challenge for P6 students who are unable to visualise the structure in 3D.
I am working on it right now and will post up the solutions soon.
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(a)
This step is not neccessarily, but for the sake of teaching purposes, let us classify the wooden blocks cut out into three groups, A, B and C. Note that the blocks in each individual group are similar.
There is 1 block in Group A, which is the uppermost.
There are 2 blocks in Group B, which are the largest blocks.
There are 3 blocks in Group C, they are the remaining blocks.
Total Volume of entire wooden structure
= 300cm X 150cm X 150cm = 6 750 000 cm^3
Volume of block in Group A
= 50cm X 50cm X 150cm
= 375 000 cm^3
Volume of blocks in Group B
= 2 X ( 30cm X 100cm X 150cm )
= 900 000 cm^3
Volume of blocks in Group C
= 3 X ( 100cm X 50cm X 30cm )
= 450 000 cm^3
Volume of Art Piece
= Volume of entire wooden structure - Volume of all the wooden blocks
= 6 750 000 cm^3 - 375 000 cm^3 - 900 000 cm^3 - 450 000 cm^3
= 5 025 000 cm^3 = 5.025 m^3
(b)
Amount of dices that could be cut out from the block in Group A
= 3 X 3 X 10 = 90 dices
Amount of dices that could be cut out from the blocks in Group B
= 2 X ( 10 X 6 X 2 ) = 240 dices
Amount of dices that could be cut out from the blocks in Group C
= 3 X ( 6 X 3 X 2 ) = 108 dices
Largest number of dices that could be made from the wooden blocks
= Total amount of dices
= 90 + 240 + 108
= 438 dices