Q1) Sally bought some identical red files. The cost of each file is $1.40. When she bought 1 more blue file at $4.60, it increases the average cost of the red and blue files to $1.80. How many files did Sally buy altogether?
Q2) Amy bought an equal number of orangs and pears. The oranges were sold at 5 for $3 and the pears were sold at 4 for $5. She paid $13 more for the pears than the oranges. How much did she pay in all?
Originally posted by Ngml:Q1) Sally bought some identical red files. The cost of each file is $1.40. When she bought 1 more blue file at $4.60, it increases the average cost of the red and blue files to $1.80. How many files did Sally buy altogether?
Q2) Amy bought an equal number of orangs and pears. The oranges were sold at 5 for $3 and the pears were sold at 4 for $5. She paid $13 more for the pears than the oranges. How much did she pay in all?
1)
Amount more blue file cost than red file
= $4.60 - $1.40 = $3.20
Additional average cost spread across all files
= $1.80 - $1.40 = $0.40
Amount of total files
= $3.20 / $0.40 = 8 files
2)
5 oranges = $3 and 4 pears = $5
Since the same amount of oranges and pears were bought, we should try making the amount of oranges and pears equal first.
20 oranges = $12 and 20 pears = $25
Difference in cost between oranges and pears
= $25 - $12 = $13
= > This is the amount of oranges and pears bought
= > Total cost = $12 + $25 = $37
Thank you very much for the help.