1) Mr Tan bought 3 times as many badges as toycars and spent $144 in total. He spent $84 more on toycars than on badge. Given that a toycar cost $10.40 more than badge, what is the cost of a badge?
ANSWER: $1
2) Mary and Jason each have some money. If mary spent $80/day and Jason spent $40/day, Mary will have $500 left when Jason has spent all his money.
If Mary spends $40/day and Jason spent $80/day, mary will have $1100 left when Jason has spent all his money. What amount of money does Jason have?
ANSWER: $400
Q1.
Not sure if you learnt algebra but i'm using it to solve.
Badges : Toy Car
3 : 1
We know he spent $84 more on toycars than on badge.
So 144 - 84 = 60
So Badges cost = 60 / 2 = 30
Amount spend on toy car = 30 + 84 = 114
Let x be the Price of Badge
Let y be the Unit Ratio for Badges and Toy Car
114/y = x + 10.4 equation 1
30/3y = x
10/y = x equation 2
Sub equation 2 into 1
114/y = 10/y + 10.4
114/y = 10/y + 10.4y/y
114 = 10 + 10.4y
114 - 10 = 10.4y
104 = 10.4y
y = 10
Sub y=10 into equation 2
10/10 = x
x = 1
Therefore, the price of a badge cost $1.
Q2.
Let x be the no. of days where mary left $500
Let y be the no. of days where mary left $1100
When Mary left $500
Mary spend $80/day --------> 80 x + $500
Jason spend $40/day --------> 40x
When Mary left $1100
Mary spend $40/day ---------> 40y + $1100
Jason Spend $80/day---------> 80 y
40 y + 1100 = 80 x + 500 ----- equation 1
40 x = 80y
x = 2y ------ equation 2
Sub equation 2 into 1
40y + 1100 = 80(2y) + 500
40y + 1100 = 160y + 500
-120y = -600
y = 600/120
y = 5 days
Amount Jason have = 5 days X 80 = $400.
Hope my solution helps. ^^