P6 Maths - Q3

• kkhing

  5 Sep 09, 09:00

  

• Forbiddensinner

  5 Sep 09, 11:14

  Originally posted by kkhing:

  

  Though this is a P6 question, algebra is required.

  This question is honestly not Pri standard.

  Let breadth of square be x.

  Total area of everything = area of all rectangles - area of all squares

  (24+x)(36+3x) = 22(6X(6+x)) - 3x^2

  Solving this, you will find x.

  Area of all squares = 3x^2, so you just need to sub the value of x in.

• rurumoo

  7 Oct 09, 16:49

  Hiya,

  If you look at the length of the BIG rectangle, you can see that it is made up of the lengths of 6 small rectangles. Let's call this length L, shall we? :)

   

  OK, if the BREADTH of the small rectangles are 6cm, we can note that the length of the large rectangle is made up of 3 breadths and 3 lengths. Now, this is the same as 6 lengths.

  So, 6L = 3B + 3L

  3L = 2L = 18cm

  L = 9cm

  9cm-6cm = 3cm

  3cmx3cm = 9cm square (area of 1 small white square)

  9cmx3= 27cm square, which is your answer.

   

  I hope I helped. it was actually fun, lol :D

   

   

• wAt3v3r

  7 Oct 09, 22:53

  I think you made some typo errors.=x

  the big rectangle is made up of the length of 5 small rectangles.

  so 5L = 3B + 3L

  and the following step is

  2L = 3B = 18

  the rest of the working would be correct. (:

• kenn3th

  7 Oct 09, 23:02

  Algebra is taught in primary schools now ):

• wAt3v3r

  7 Oct 09, 23:19

  yes it is, but it is very basic. pri sch students are usually not required so solve qns using algebra.