The figure shows 3 identical semicircles, a circle and a square OABC enclosed in a bigger semicircle. O is the centre of the bigger semicircle and one of the small semicircles. B is the circle of the circle. Given that AB is 7 cm, find the total area of the shaded parts. (Take pie = 22/7).
area of triangle ABC = 1/2 x 7 x 7 = 24.5
area of Quadrant ABC = 1/4 x 22/7 x 7^2 = 38.5
Area of shaded region = 4 x (38.5 - 24.5) = 56 cm^2
area of triangle 1/2 x 7 x 7 = 24.5
isn't that the slant height?
Originally posted by ASKL!:area of triangle 1/2 x 7 x 7 = 24.5
isn't that the slant height?
area of triangle is 0.5 x base length x height perpendicular to base ah...
Originally posted by ASKL!:area of triangle 1/2 x 7 x 7 = 24.5
isn't that the slant height?
ABCD is a square. Therefore angle ABC = 90.
AB(Height) = 7 and AC(Base) = 7