Electrolysis

• Audi

  15 Sep 09, 22:45

  In an electrolysis experiment, the same amount of charge deposited 16g of Cy and 6g of Ti. What was the charge on the titanium ion? +4 is the answer.

  Well, how do you solve this? (I did this question before but forgot how to do it now)

  Thanks

• UltimaOnline

  15 Sep 09, 22:49

  Find the no. of mols of electrons transferred. For every mol of electron accepted per mol of the metal cation, the OS decreases by 1. Let the OS of Ti cation be X. Mols of electrons accepted per mol of Ti = 4 Since the OS of Ti metal is 0, hence X + (-4) = 0 X = +4
• yiha093

  16 Sep 09, 00:33

  hey ultima i dun understand where u are going, i can only deduce

  16/64=  0.25mol of electron passed through it.

  means 0.25mol pass through TI .

  then what do i do with that figure ?

   

• qdtimes2

  16 Sep 09, 00:42

  0.5 mol of electron is needed to balance the charge of Cu2+ ion

• yiha093

  16 Sep 09, 00:48

  no i still dun understand, can sum1 give a step by step asnwer?

   

• qdtimes2

  16 Sep 09, 12:58

  Cu2+ +2e- = Cu

  2 electrons (negative charges) are needed to balance the 2+ positive charge of Cu ion

  0.25Cu2+ + 0.5e- = 0.25 Cu

  0.125TiX + 0.5e- = 0.125 Ti

  TiX + 4e- = Ti

  so X = 4+

• UltimaOnline

  16 Sep 09, 13:54

  qdtimes2's explanation is correct. Just in case yiha093 is still confused : yiha093's error is in the statement, "16/64= 0.25mol of electron passed through it". 0.25 mol is of Cu(s). Which means 0.5 mol of e- is transferred. Which means 0.125 mol of Ti cations accepts 0.5 mol of e-. Which means each mol of Ti cation accepts 4 mol of e-. Which means initial O.S. of Ti must be +4. +4 (O.S. of Ti cation) + (4 e-) = 0 (O.S. of metal solid means metal atom means O.S. is zero)
• SBS n SMRT

  17 Sep 09, 14:49

  for this question, i just remember that ti charge is 4+