A regular hexgon ABCDEF, has centre O. Vector OA = a , vector OB = b
I have given you guys the guiding questions. The actual question is below. Please explain to me how to prove in equilateral triangle. E Maths paper tomorrow, so yea, help is needed urgently.
Express as simply as possible , in terms of a and/or b,
Vector DO, AB, and DB
Explain why |a| = |b| = |b-a|
The points X,Y and Z are such that
Vector OX = a + b, Vector OY = a - 2b , and OZ = b - 2a
Express as simply as possible in terms of a and/or b,
Vector AX, Vector YX
Express as simply as possible in terms of a and/or b, the vector XZ
Show that triangle XYZ is equilateral. (This is the question)
Hi,
To show that XYZ is equilateral, we show that all three sides are equal in magnitude.
Vector XY = -3b, Vector YZ = -3a + 3b = 3(b - a), Vector XZ = -3a.
Now we consider their lengths, i.e. XY = 3|b|, YZ = 3|b - a|, XZ = 3|a|.
By the fact that |a| = |b| = |b - a| (because a regular hexagon is formed by six equilateral triangles), the lengths are equal and we are done.
Thanks and good luck!
Cheers,
Wen Shih