*evil mode*
i hope that it was very very very very difficult and all of u will fail ^ .^
*laughs*
*angel enters*
It will be the reverse in reality. It will be a record of A-scorers this year!
*smiles*
Originally posted by wee_ws:*angel enters*
It will be the reverse in reality. It will be a record of A-scorers this year!
*smiles*
But papers getting easier and easier make it very hard to tutor...
The schools will continue to set extremely tough mid/end/prelim papers...
tutors being constantly pressured by the those papers will be still be forced to go for complexity when the real need is for consistence in basic concepts/questions and techniques of checking.
Luckily my friend told me it is tough HAHAHAHAHAHA
the paper was okay with a few unique questions.. my answers are:
1. a =3, b=-8
2. x< 2.72 wrong 0<x<2.72 is correct..
3. b = 2, a =4
4i) 2 2/3
ii) y = 16
5. k = 6
6i) -2< or equal to x < or equal to 5
ii) c = 10
7. (2, 1.5)
8ii) pie/3, pie/2, 2pie/3
9i) max = 2, min = -4
ii) amplitude = 3
iii) period = 1080 drgs
iv) smallest value = 58.4 drgs
10ii) k = 0.072, m0 = 54.8
iii) 11.2 h
11i) y = x/4 + 6
ii) B = (8,8)
iii) C = (18,2)
iv) 42 wrong, 102 units square correct
12i) 12x / (4x - 1)^0.5
ii) 0.25units /s
iii) 2.5
Shit my friend lied to me... it was easy.
The time now is 5:25pm and I started at 5pm and finished it already....zzz
Ya it was easy. But then how do you get the answer for 11iii) the coordinates of C? My geometry quite weak sia.
Originally posted by Han chiang:Ya it was easy. But then how do you get the answer for 11iii) the coordinates of C? My geometry quite weak sia.
i sub in the eqn of CD to the length of CD
wa sian liao la.... xD
Still dont understand T_T
I think the year's A1 cut off will be >155/180 and >145/180.
And one of my students lost 25 already...zzz... she died where my friend told me most people died... the increasing function, trigo graph and coordinate geometry. sianzzz
Most of them lost around 10 marks.
wa cut off so low ah :O
Originally posted by Mikethm:I think the year's A1 cut off will be >155/180 and >145/180.
And one of my students lost 25 already...zzz... she died where my friend told me most people died... the increasing function, trigo graph and coordinate geometry. sianzzz
Most of them lost around 10 marks.
increasing function was tricky
if i didnt remeber wrongly my answer is { 0<x<e , xE|R}
Originally posted by Han chiang:Still dont understand T_T
let coordinates of C be (x, y)
CD = 2AB = 2(sqrt 64) = sqrt( (x-2)^2 + (y + 2)^2)
then sub in the eqn of CD's x or y inside the sqrt( (x-2)^2 + (y + 2)^2)
wa sian there goes my 4 marks...
AM paper 1: Manageable
only Q 2 dunnoe how to do
Plus, the coordinates of C can also use vectors to solve
Vector AB = 0.5 vector DC and so on.......
Solutions to this question by accurate drawing will not be accepted means what?
o.o vector also can?
yeah should be, but u also can use gradient and midpoint (?)
Originally posted by Han chiang:Solutions to this question by accurate drawing will not be accepted means what?
tat means no plot on graph paper and solve using that manner
Paper 2 Prediction:
Binomial theorem
Partial Fraction, probably mixed with differentiation and integration
Matrices
Discriminant
Polynomial
Trigo (R Formula)
Plane Geometry!!
Maxima and Minima
Integration for area under curve
Kinematics
Quadratic Equation (sum of roots ; product of roots)
Originally posted by qdtimes2:let coordinates of C be (x, y)
CD = 2AB = 2(sqrt 64) = sqrt( (x-2)^2 + (y + 2)^2)
then sub in the eqn of CD's x or y inside the sqrt( (x-2)^2 + (y + 2)^2)
A more effective solution would be...
Vector CD = 2 Vector AB
CO+OD = 2(AO+OB)
OC = OD + 2OA -2OB
3 steps instead of 2 pages of working...
Originally posted by Mikethm:A more effective solution would be...
Vector CD = 2 Vector AB
CO+OD = 2(AO+OB)
OC = OD + 2OA -2OB
3 steps instead of 2 pages of working...
yeah, i do this =)
Originally posted by SBS n SMRT:yeah, i do this =)
Then u die liao coz I typo the direction wrongly.
My HOD posted up the answers for us.
I scored 59/80.
Damn.
Gonna need 90/100 at least for an A.