how to find the derivative of this eqn
P(x) = 6x - (x^2 / 1000) - 5000
Originally posted by fireice rox:how to find the derivative of this eqn
P(x) = 6x - (x^2 / 1000) - 5000
3x^2 - (1/3000) x^3 - 5000x + C, where C is a constant.
Finally some maths : D
Originally posted by Forbiddensinner:3x^2 - (1/3000) x^3 - 5000x + C, where C is a constant.
Finally some maths : D
Hahaha welcome back FS!
Btw, isn' finding derivative differentiating the eqn, not integrating it (which was what you did)?
I thought it would be like
P(x) = 6x - (x^2 / 1000) - 500
P(x) ' = 6 - x/500
Do enlighten me o.0
Originally posted by Dejomel:
Hahaha welcome back FS!Btw, isn' finding derivative differentiating the eqn, not integrating it (which was what you did)?
I thought it would be like
P(x) = 6x - (x^2 / 1000) - 500
P(x) ' = 6 - x/500
Do enlighten me o.0
can P(x) ' be derivative further?
Originally posted by Dejomel:
Hahaha welcome back FS!Btw, isn' finding derivative differentiating the eqn, not integrating it (which was what you did)?
I thought it would be like
P(x) = 6x - (x^2 / 1000) - 500
P(x) ' = 6 - x/500
Do enlighten me o.0
You are right : ( Integrand then is integrate.
Careless mistake, need to read carefully next time round.
And to FI rox, if you differentiate again, it will become -1/500