Find the laplace trans form for the following functions
1i*) 4cos^2 (2t)
oh..its u again.
Haha yup. nvm found the answer need to use this identity. Can show me how to derive this identity?
ummm....i burnt all my tutorials many years ago.
Hi,
First 2 results are double-angle identities, covered in Additional Maths.
As for the 3rd result, consider RHS:
1. numerator = 1 - cos(2u) = 1 - [ 1 - 2(sin u)^2 ]
2. denominator = 1 + cos(2u) =1 + [2(cos u)^2 - 1 ].
Thanks.
Cheers,
Wen Shih
hey wee,
slowly lookin like what i did in past....from formulas!!!!thats odd.......hmmmm..used to go on questions with answers on 1 whole page in past .
Hi Wireless,
You may read a short article I have written at:
http://weews.webs.com/laplacetransforms.htm
Hope it'll help to clarify your understanding of the topic.
Thanks.
Cheers,
Wen Shih
wee,
damn...u selling past year tutorials???.....u accept paypal??:)
download all worked out model answers too??wished they had the internet in those days......