Differentiaton & Integration

• sbst275

  12 Sep 10, 17:03

  any maths siao can advise?

  Now trying to scratch my head aft eons...

  ds/dt = 15t (4t sq - 6) cube , s(1) = 6.

  d sq/ d x sq = 4 cos (6x - PI)

• Forbiddensinner

  12 Sep 10, 21:58

  Originally posted by sbst275:

  any maths siao can advise?

  Now trying to scratch my head aft eons...

  ds/dt = 15t (4t sq - 6) cube , s(1) = 6.

  d sq/ d x sq = 4 cos (6x - PI)

  What is the question? 

  The only thing I can do here is find S for you.

  ds/dt = 15t (4t^2 - 6)^3

  S = (15/32)(4t^2 - 6)^4 + C

  S(1) = 6, so:

  (15/32)(4(1)^2 - 6)^4 + C = 6

  (15/32)(16)  + C = 6

  C = 6 - 15/2

  C = -3/2

  S = (15/32)(4t^2 - 6)^4 - 3/2