Y is directly proportional to X^2
Given: Y is 10 for a certain value of X.
QuestionL Find the value of X when Y is halved.
I tried many times but still failed to solved.
Originally posted by ProjectsMates:Y is directly proportional to X^2
Given: Y is 10 for a certain value of X.
QuestionL Find the value of X when Y is halved.
I tried many times but still failed to solved.
y=kx^2, where k is a constant.
Since y =10, we have:
10=kx^2
k = 10/x^2
let the certain value of x be a.
When y is halved, y = 5
5 = kx^2
5 = (10/a^2)x^2
x^2 = (1/2)a^2
x = (1/sqrt2)a or x = -(1/sqrt2)a
If you want an exact answer, I cannot give you one, since the value of x can vary according to k.