Sec 2 Maths Problem

• kkhing

  19 Jan 11, 17:29

  

• kkhing

  19 Jan 11, 17:33

  Sorry, typo error, the condition should be if a=b, what is the value of W?

• Bluehawk156

  19 Jan 11, 17:45

  Are you sure the question is right?

• Lee012lee

  19 Jan 11, 19:53

  n(Q) = a + b

  Since a = b (given by TS in his 2nd corrected post), n(Q) = a + a = 2a

  Given that n(Q) = 32, 2a = 32, a = 16 ie b = 16 too

  n(P) = b + c = 46

            16 + c = 46

             c = 30

  Hence,

  a + b + c + W = 60

  16 + 16 + 30 + W = 60

  62 + W = 60

          W = - 2 but W cannot be negative

  Hence, this question is WRONG.

  PS : In set notation, we do not write P(n). Instead. we write n(P) ie the number of

          elements in the set P.

• Whee159

  22 Jan 11, 21:27

  lols this qns ain't making sense...

  if a = c, why

  (a + b) not = to (c + b)?

  or is it just me... PS. long time nvr touch maths xP