Help with indices

• Stampboy123

  7 Apr 11, 18:12

  Hi,

  (3^2/3) x (4^7/3) x (6^1/3)

  Stuck with this qns for almost one hr....

   

• FireIce

  7 Apr 11, 18:23

  3^2(1/3) x 4^7(1/3) x 6^1/3
  
  = 9^1/3 x 16384^1/3 x 6^1/3
  
  = (9 x 16 384 x 6) ^1/3
  
  = (884 736) ^1/3
  
  = cube root (884 736)

  = 96

• Stampboy123

  7 Apr 11, 18:29

  must be done w/o calculator. if using your method its too tedious. do you have other methods?

• ditzy

  7 Apr 11, 18:36

  Cannot use calculator then use the below indices law with fractional indices loh.

  y^a × y^b = y^a+b

  (y^a)^b = y^a×b

  A fractional power means that you have to take a root of the number. For example, 4^½ means take the square root of 4 = 2. Similarly, x^1/3 means take the cube root of x.

  We can use the rule (y^a)^b = y^a×b to simplify complicated index expressions.

  Example

  (1/8)^-1/3; = [(1/8)^-1]^1/3 = [8]^1/3 = 2

  Amazing shit right this google?

   

• FireIce

  7 Apr 11, 18:38

  4 can be 2^2 (oso not helpful in this eqn)

   

  3 and 6 no have root

• Stampboy123

  7 Apr 11, 19:43

  i solve ald

  3^2(1/3) x 4^7(1/3) x 6^1/3

  =(9x6)^(1/3)x2^(14/3)

  =3x2^(1/3)x2^(14/3)

  =3x2^5

  =96

• ditzy

  7 Apr 11, 19:49

  See, google saves the day again, now thank me.

• Stampboy123

  7 Apr 11, 20:00

  thanks.

• Darkness_hacker99

  7 Apr 11, 21:58

  Please come back again!