To provide vitamin additives for patients, a hospital dietician has two prepackaged mixture available. Mixture 1 contains 6 grams of vitamin C and four grams of niacin; mixture 2 contains 5 grams of vitamin C and 3 grams of niacin. On an average day, she needs 125 grams of vitamin C and 79 grams of niacin.
Solve by using simultaneous eq.
solve ximi?
find wat?
Pardon me, the last time I did a maths questions was 4 years ago.
I think the question is asking to find the numbers of prepack mixture 1 and 2 require to mee the daily requirement of vitamin supplements.
sorry. it is to find the number of mixture for mixture1 and mixture 2
I did the esti method and model.
so my answer is 10 packs of Mixture 1, 13 packs of Mixture 2. Though I can't solve the problem using the way you asked for, but..... i did it in an alternative method :D
nvm i solve the problem alrd.
6x+5y= 125 , 18x+15y= 375
4x+3y= 79 , 20x+15y= 395
Therefore 2x= 20 and x=10.
Sub x=10
4(10)+3y=79
3y=39
y=13.
Hi,
The question seems incomplete, so understanding it is difficult.
Consider these steps:
1. Let x represent the number of mixture 1 and y represent the number of mixture 2.
2. Form an equation involving vitamin C, based on its average day's need. Form an equation involving niacin in a similar way.
3. Solve the two linear equations by substitution, elimination, or inverse matrix method.
Thanks.
Cheers,
Wen Shih