Hi, I am here with another mole concept question.
What is the vol. of distilled water needed to be added to 60cm3 of sulfuric acid of 2.0mol/dm3 to produce a 0.3mol/dm3 sulfuric acid?
Thank you.
Originally posted by Jasmine ngjiamin:Hi, I am here with another mole concept question.
What is the vol. of distilled water needed to be added to 60cm3 of sulfuric acid of 2.0mol/dm3 to produce a 0.3mol/dm3 sulfuric acid?
Thank you.
Let vol of distilled water added be x dm3.
Moles of H2SO4 present = (60/1000)(2.0) = 1.2x10^-1 mol
Final molarity of H2SO4 = 0.3 mol/dm3
Moles / Volume = 0.3 mol/dm3
( 1.2x10^-1 ) mol / ( (60/1000) + x) dm3 = 0.3 mol/dm3
Solve for x.
0.3x + 1.8x10^-2 = 1.2x10^-1
x = 3.4x10^-1 dm3 = 340 cm3
thank you
Originally posted by Jasmine ngjiamin:thank you
You're welcome, Jasmine.
Remember, in Chemistry calculations, Algeba is your best friend!