Hi, another question here:
300cm3 of 0.5mol/dm3 of nitric acid was added to 200cm3 of 2mol/dm3 of nitric acid, calculate the final concentration of nitric acid produced.
This is my solution:
(300/1000) x 0.5 = (3/20) mol
(200/1000) x 2 = (2/5) mol
total: (3/20) + (2/5) = (11/20) mol total vol: 300+200 = 500
concentration = mol / vol = 0.5 dm3
= (11/20) / 0.5
= 1.1 mol/dm3
is this correct?
didn't check your numerical value, but your working is right.
ok thks^^