"O" Level E.Maths Question : Nov 2009 P1 Q13(a)
When d is 12 cm, the answer for t is given as 2 seconds.
My working is
V1/V2 =(d1/d2)^3 where V1 = volume of water when d1 = 12 cm^3
V2 = voulme of water when d2 = 24 cm^3
V1/V2= (12/24)^3
V1/V2= 1/8
V1=(1/8)V2
The container is filled with water after 8 seconds.
So, V2 ------ 8s
V1= (1/8)V2 ------ ?s
(1/8) x 8 = 1s.
So, when the depth is 12 cm, t is 1 second.
Did I make a mistake or the given answer is incorrect ?
Thanks.
PS : SAP solution has used A1/A2 = (d1/d2)^2 to get the answer t is 2 seconds.
I disagreed with the use of A1/A2 as water is poured into the container, we should use V1/V2. So, the answer should be t = 1 second. Please correct me if I am wrong. Thanks.
Always indicate the subject in your title header. "Physics" or "Chemistry" or "Mathematics" etc.
Originally posted by UltimaOnline:Always indicate the subject in your title header. "Physics" or "Chemistry" or "Mathematics" etc.
Hi UltimaOnline,
Thanks for the reminder as it had been many months that I last visited sgforums.com homework forums.
I will make immediate changes to my earlier post.
Thanks.
Regards.
Lee012Lee
My year o level qns, the answer given is correct, as Area should be used as if I did not remember wrongly, the height is constant. (Trick!)
Refer to http://www.exampaper.com.sg/wp-content/uploads/gce-o-level-2009-emaths-4016-paper-1-solutions.pdf
for full answers
Originally posted by SBS n SMRT:My year o level qns, the answer given is correct, as Area should be used as if I did not remember wrongly, the height is constant. (Trick!)
Refer to http://www.exampaper.com.sg/wp-content/uploads/gce-o-level-2009-emaths-4016-paper-1-solutions.pdf
for full answers
Hi SBS n SMRT,
Thanks for the reminder that the height is constant and I have discovered my mistake and thanks for the url link.
Regards,
Lee012Lee