Hi,
This question is from RI(JC) 2010 paper.
To obtain B from A via a clockwise rotation of (2/3)pi about the origin, we multiply e^(-(2/3)pi*i) to the complex number represented by A.
I believe students are more familiar with the relationship between iz and z, where iz is obtained from z via an anticlockwise rotation of pi/2 about the origin. In fact, iz is equivalent to z multiplied by e^((pi/2)*i).
Thanks.
Cheers,
Wen Shih
oh god...i'm so not looking forward to JC...
Hi,
Complex Numbers is a topic taught at JC 2 and it is a difficult topic for most students.
In JC 1, the challenges are:
1. General Paper
2. Project Work
3. Fast-paced lectures and tutorials
4. Frequent class and lecture tests, typically with no time to complete.
However, one can pick up great life-skills (i.e., reading, writing and communication skills, ability to embrace an ever-changing, ever-challenging globalised economy and workplace where short deadlines to deliver results are a norm, etc.) from these.
Thanks.
Cheers,
Wen Shih
Well, they're called complex numbers for a reason.
To TS, u are Daniel798 huh? Because something identical was posted here:
http://forums.sgclub.com/singapore/complex_numbers_374428.html