Hi(:
can you help me out with this question?
Solve the following sets of simultaneous equations:
2x=1-3y
3y^2-x^2=2
2x = 1- 3y
x = (1 - 3y) / 2
Sub x = (1 - 3y)/ 2 into another eqn.
3y^2 - ((1 - 3y)/2)^2 = 2
3y^2 - (1-3y)^2 / 4 = 2
12^2 - (1-3y)^2 = 8
12^2 -1 + 6y - 9y^2 - 8 = 0
3y^2 + 6y - 9 = 0
y^2 +2y - 3 = 0
(y + 3) (y - 1) = 0
y = -3 y = 1
2x = 1 - 3(-3) 2x = 1 -3(1)
2x = 10 2x = -2
x = 5 x = -1
Therefore, x = 5 y =-3 , x = -1 y = 1
Ps I got bored lol.
Hi POP222,
This type of question has a fixed pattern that you ought to grasp it to score full marks:
1. Express x in terms of y or y in terms of x.
2. Substitute into the non-linear equation, leading to a quadratic equation in terms of y or in terms of x.
3. Solve the quadratic equation to obtain two values of y or x.
4. Obtain the values of the other variable.
In the 2011 exam, the student is expected to form the equations based on a word problem (please refer to P1/Q6 for details). This is a new skill expected of a student who wishes to obtain distinction in the subject.
Thanks.
Cheers,
Wen Shih