OK
Trying to do some log qns to refresh my memories on Maths.
For simplicity, I'll use 'a' as base power.
log a x = b ==> x = a^b
log a x + log a y = log a x*y
log a x - log a y = log a x/y
y log a x = log a x^y
What about if it's like this z (log a x)^y?
Hi,
That can't be simplified further, thanks.
Cheers,
Wen Shih
I concur. Mathlab tells me the same thing.
Thanks