Keith went shopping with thrice as many S$5 notes as S$2 notes . After he used 28 pieces of S$5 notes , he had 5 times as many S$2 notes as S$5 notes left . Find the total value of his remaining S$5 and S$2 notes .
Thanks
I would suggest using a model to better illustrate the problem.
But here's the algebra method
let original no. of $5 notes be x
let original no. of $2 notes be 1/3 x
5(x-28) = 1/3 x
15(x-28) = x
14x = 420
x = 30
value of remaining $5 notes = (30-28) * 5 = $10
value of remaining $2 notes = (30/3) * 2 = $20
Total value= $30
Hi Lolerchild ,
Thanks for your reply . However , I need the answer shown in model method . Need your assistance .
Regards .
as you can see,
in the beginning you have 3 times as many $5 as $2.
After using 28 notes of $5, you are left with 5 times as much $2 as $5.
Hence
14 blocks = 28 notes.
1 block = 2 notes
remaining $5 notes= 1*2 (2*$5=$10)
remaining $2 notes= 5*2 (10*2=$20)
total remaining=$30