QUESTIONS -
1)WHY ARE THE MPT OF SAMPLE 1 AND 2 DIFFERENT?
2) IDENTIFY WHICH ISOMER THE STUDENT ANALYSED.
Nitration of benzene
Reacted samples of phenol with reagents
Seperated the 2 organi prod from reaction by chromatography
Suspected 2 products were structural isomers with NO2 substitudes at 2 and 4 positions
Suspected structures =
2-nitrophenol
4-nitrophenol
Measured MPT of one of products, then recrystallised sample and took MPT of recrys. product
Sample 1 = MPT before recrys. 104-108 degres
2 = MPT after recrys - 110-114 degres
MPT from databse of structural isomers = 2-nitro isomer = 44 degrees
4-nitro isomer 112 degrees
Jennifer the Awesome, after this question, I will not help out with further questions until you've addressed the questions that I've asked earlier but which you've ungraciously ignored. "Which course of study are you asking these questions for, and which country is this based in?"
--------------------------------------------
Ortho-nitrophenol has a lower melting and boiling point compared to para-nitrophenol, because ortho-nitrophenol's capacity for hydrogen bonding has been partially used up to form intramolecular hydrogen bonds, and thus has less extensive intermolecular hydrogen bonds.
Oho, somebody's playing with interesting substances.